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Step-by-step explanation:
Given -
- ax² - 9x + 15 is a quadratic polynomial and product of its zeroes is -6
To Find -
Value of a
As we know that :-
- Product of zeroes = c/a
It means,
» -6 = 15/a
» a = 15/-6
- » a = -5/2
Hence,
The value of a is -5/2
Verification :-
ax² - 9x + 15
» -5x²/2 - 9x + 15 = 0
» -5x² - 18x + 30 = 0
As we know that :-
- αβ = c/a
» -6 = 30/-5
» -6 = -6
LHS = RHS
Hence,
Verified..
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a = -5/2
ax² - 9x + 15 is a quadratic polynomial and product of its zeroes is -6.
Value of a ?
products of zeroes = c/a
-6 = 15/a
a = -15/6
a = -5/2
ax² - 9x + 15
-5x²/1 - 9x + 15 = 0
-5x² - 18x + 30 = 0
αβ = c/a
-6 = 30/-5
-6 = -6
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