Question

a particle executing S.H.M having amplitude 0.01m and frequency 60Hz. determine maximum acceleration of particle?​

Answer 1

hey mate❤️

your answer:-

Maximum acceleration

\\*= a\omega^{2} = a\times4\pi^{2}n^{2} \\* =0.01 \times 4\times (\pi)^{2} \times (60)^{2} \\*=144\pi^{2}

Accelration in SHM -

A = \frac{dV}{dt} = a\omega ^{2}\cos \omega t

A = -\omega ^{2}y [Formula]

- wherein

Rate of change of velocity.

Answer 2

❤❤.... $\huge\mathfrak{Hlo\:Reetu}$....... ❤❤

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