a particle executing S.H.M having amplitude 0.01m and frequency 60Hz. determine maximum acceleration of particle?
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hey mate❤️
your answer:-
Maximum acceleration
\\*= a\omega^{2} = a\times4\pi^{2}n^{2} \\* =0.01 \times 4\times (\pi)^{2} \times (60)^{2} \\*=144\pi^{2}
Accelration in SHM -
A = \frac{dV}{dt} = a\omega ^{2}\cos \omega t
A = -\omega ^{2}y [Formula]
- wherein
Rate of change of velocity.
riya833:
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