Math, asked by dhananjay67, 1 year ago

find the sum of all number all natural number from 1 to 200 which are divisible by 3

Answers

Answered by sahil3441
6

The A.P. is 3,6,9,.....,198 ,a=3,d=3

  1. tn=a+(n-1)d

198=3+(n-1)d

n=66

sn=n÷2{2a+(n-1)d}

=33{2×3(66-1)3}

=33×101

=6633

ANS.6633

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