find the sum of all number all natural number from 1 to 200 which are divisible by 3
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The A.P. is 3,6,9,.....,198 ,a=3,d=3
- tn=a+(n-1)d
198=3+(n-1)d
n=66
sn=n÷2{2a+(n-1)d}
=33{2×3(66-1)3}
=33×101
=6633
ANS.6633
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