Math, asked by lalitalakhani3, 2 days ago

A particle executing SHM in a straight line AOB is found to have zero velocity when it is at points A and B whose distance from O are 'a' or 'b', respectively, and its velocity is v when it is half-way between them. Find the frequency of oscillation.​

Answers

Answered by MatricsGirl
3

\huge\bf{\underline{Solution:-}}

\small\sf{At\:point\:A\:and\:B\:velocity}

\small\sf{B\:zero\:m}

\rightarrow\small\sf{distance\:between\:A\:and\:B=a+b}

\small\sf{Amplitude\:of\:SHM=}\small\frac{a+b}{2}

\therefore\small\sf{at\:point\:M}

\small\sf{velocity=V}

\small\sf{but\:in\:SHM\:velocity\:at}

\small\sf{at\:mean\:position=AW}

\therefore\small\sf{AW=V}

(\small\frac{a+b}{2})\small\sf{W=V}

\small\sf{W=}\small\frac{2V}{a+b}

\small\sf{T=}\small\frac{2\pi}{w}=\small\frac{2\pi}{2V}(a + b)

\small\sf{T=}\frac{\pi(a + b)}{V}

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