Question

Pls solve the answer
I will give brainliest ​

Answer 1

Solutions:

Solutions:(a) Yes, since, CE = 2 units and EG = 2 units respectively

Solutions:(a) Yes, since, CE = 2 units and EG = 2 units respectively(b) Yes. Since, CE = EG as both are of 2 units. Hence PE bisect CG

Solutions:(a) Yes, since, CE = 2 units and EG = 2 units respectively(b) Yes. Since, CE = EG as both are of 2 units. Hence PE bisect CG(c) and are the line segments for which PE is the perpendicular bisector

Solutions:(a) Yes, since, CE = 2 units and EG = 2 units respectively(b) Yes. Since, CE = EG as both are of 2 units. Hence PE bisect CG(c) and are the line segments for which PE is the perpendicular bisector(d) (i) True. Since AC = 2 units and FG = 1 unit

Solutions:(a) Yes, since, CE = 2 units and EG = 2 units respectively(b) Yes. Since, CE = EG as both are of 2 units. Hence PE bisect CG(c) and are the line segments for which PE is the perpendicular bisector(d) (i) True. Since AC = 2 units and FG = 1 unit∴ AC > FG

Solutions:(a) Yes, since, CE = 2 units and EG = 2 units respectively(b) Yes. Since, CE = EG as both are of 2 units. Hence PE bisect CG(c) and are the line segments for which PE is the perpendicular bisector(d) (i) True. Since AC = 2 units and FG = 1 unit∴ AC > FG(ii) True because both are of 1 unit

Solutions:(a) Yes, since, CE = 2 units and EG = 2 units respectively(b) Yes. Since, CE = EG as both are of 2 units. Hence PE bisect CG(c) and are the line segments for which PE is the perpendicular bisector(d) (i) True. Since AC = 2 units and FG = 1 unit∴ AC > FG(ii) True because both are of 1 unit(iii) True. Since, BC = 1 unit and EH = 3 units

Solutions:(a) Yes, since, CE = 2 units and EG = 2 units respectively(b) Yes. Since, CE = EG as both are of 2 units. Hence PE bisect CG(c) and are the line segments for which PE is the perpendicular bisector(d) (i) True. Since AC = 2 units and FG = 1 unit∴ AC > FG(ii) True because both are of 1 unit(iii) True. Since, BC = 1 unit and EH = 3 units∴ BC < EH

Answer 2

Answer:

what is the page number?