Question

A particle executing SHM on a line 8 centimetre long its kinetic and potential energy will be equal when its dista distance from the mean position

Answer 1

# Answer-

2√2 cm

# Solution-

SHM along a line of 8cm hence maximum displacement (amplitude) on each side will be 4 cm.

We have to find the displacement x for which kinetic energy=potential energy

Total energy(E)= potential energy+ kinetic energy.

Hence potential energy = kinetic energy =(1/2)E=(1/2)(1/2)kA^2

where, k is force constant and A is amplitude.

Next, potential energy at displacement x is(1/2)kx^2.

Therefore

(1/2)kx^2=(1/2)(1/2)kA^2

x=A/√2

We have A=4cm

x=4/√2

x=2√2 cm

KE=PE when displacement from mean is 2√2 cm.

Answer 2

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