Question

A particle experiences a constant acceleration for 20 sec
after starting from rest. If it travels a distance S1 in the first
10 sec and a distance S2, in the next 10 sec, then
(a) S =S
(b) S = S2/3
(c) S = S/2
(d) S = S2/4​

Answer 1

Answer:

A) S1 = S2

Explanation:

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Answer 2

Solution :-

Let us consider the particle travels from point A to B in 10 s and point B to C in the next 10 s

From A to B ,

• Distance covered = S 1

• Initial velocity = 0 m/s ( rest )
• Time taken = 10 s

By using second equation of motion ,

⇒ S 1 = ut + at ² / 2

⇒ S 1 = 0 + a x 100 / 2

⇒ S 1 = 50 a

Now let us find the final velocity of the particle ,

By using first kinematic equation ,

⇒ v = u + at

⇒ v = 0 + at

⇒ v = 10a

From B to C

• Initial velocity (v) = 10 a
• Time taken ( t ' ) = 10 s
• Distance traveled = S2

By using second equation of motion ,

⇒ S 2 = v t' + at' ² / 2

⇒ S 2 = 10a x 10+ a x 100 / 2

⇒ S 1 = 100 a + 50 a

⇒ S 1 = 150 a

S 2 = 3 x 50  a

we know that ,

S 1 = 50 a

Hence ,

⇒ S 2 = 3 S 1

⇒ S 1 = S2 / 3