Question

A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance s1 in the first ten seconds, and a distance s2in the next 10 seconds then?​

Answer 1

Answer:

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Explanation:

As acceleration is constant for 20 sec after starting from rest so

S1=ut +1/2 ×at^2

S1=0×10 +1/2 ×a×100

So,S1=50a

Now,S1+S2=0×20+1/2 ×a×20^2

S1+S2=200a

As, S1=50a

50a +S2=200a

S2=150a

Hence S1/S2=50a/150a

S2=3S1