Physics, asked by pplsen7700, 1 year ago

A particle experiences constant acceleration for 20 seconds after starting from rest. if it travels a distance S1 in the first 10 seconds and distance S2 in the next 10 seconds, then

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Answered by sauravh
19

let constant acceleration is a

distance travels in 20 seconds 

s = 0*20+a*20²/2

s = 200a -------------(1)

distance travels in first 10 seconds 

s1 = 0*10+a*10²/2

s1 = 50a -----------------(2)

distance travels in next 10 seconds 

s2 = s-s1

s2 = 200a-50a = 150a ----------------(3)

s2/s1 = 150a/50a = 3

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Answered by greathishanth
3

it is your answer hope it is helpful

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