Physics, asked by Jezneel5960, 11 months ago

A particle experiences constant acceleration for 20s after starting from rest if it travels a distance s1 in the first 10 second and distance s2 in next 10 second then s2 =?

Answers

Answered by Anonymous
8
Distance traveled in first 10 seconds
      
S1 = u t + 1/2 a t²  = 0 t + 1/2 a 10² = 50 a

Total distance traveled in 20 seconds =
    
S = u t + 1/2 a t² = 0 t + 1/2 a 20² = 200 a

Distance traveled from 10s to 20s = S2 = 200 a - 50 a = 150 a


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Answered by divyanshi261
9
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