Physics, asked by ajayyadav89, 1 year ago

a particle fall on earth 1) from infinity ,2) from height 10 times the radius of earth . the ratio of the velocities gained on reaching at the earth surface

Answers

Answered by JVJ1
3

Answer:√11:√10

Explanation:

Answered by hdhatar
0

Answer:\sqrt{11}:\sqrt{10}

Explanation:

T.E=K.E+P.E=1/2mv^{2}+(_GMm/r)

  1. At surface of earth, T.E=1/2mv^{2}+(_GMm/R) Where v is velocity
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