Question

A particle has a displacement of 12 m toward the east and 5 m toward the north and then 6 m vertically upwards find the magnitude of the sum of these three displacement

Answer 1

Answer:

x will be displacement

by using Pythagoren theroum

x

$x {}^{2} = 6 {}^{2} + 5 {}^{2} \\ x {}^{2} = 61 \\ x = \sqrt{61}$