Question

A particle has a displacement of 12 m towards east,
then 5 m towards north and then 6 m vertically upwards.
What is the magnitude of the sum of these displacements ?

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Answer 1

Explanation:

We have to use vector..

To find displacement, we have to take tge root of addition of squares of distance covered ...

Displacement =√( 12^2 + 5^2 + 6^2)

= √( 144+ 25+ 36)

= √ 205

= 14.31 m

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Answer 2

AnSweR:

By Pythogras Theorem,

$→\;{\sf{(AN)² = (AE)²+(EN)²}}$

$→\;{\sf{(AN)² = (12)²+(5)²}}$

$→\;{\sf{(AN)² = 144+25}}$

$→\;{\sf{AN = \sqrt{169}}}$

$→\;{\sf{AN = \sqrt{13²}}}$

$◕➜\;{\pink{\bf{AN = 13cm}}}$

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