A particle has an initial velocity of 3i+4j and an acceleration of 0.41+ 0.3). Its speed after 10 s is
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Hi ,there !!!
here is your answer !!!
v = u + at
v = 3i + 4j + 10 ( .4i + 0.3j )
v => 6i + 8j
|v| = √ ( 6)² + (8)²
| v| = 10 m/ s
hope it helps you !!
thanks !!
Ranjan kumar
here is your answer !!!
v = u + at
v = 3i + 4j + 10 ( .4i + 0.3j )
v => 6i + 8j
|v| = √ ( 6)² + (8)²
| v| = 10 m/ s
hope it helps you !!
thanks !!
Ranjan kumar
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