Which equation represents a nonlinear function?
x(y – 5) = 2
y – 2(x + 9) = 0
3y + 6(2 – x) = 5
2(y + x) = 0
Answers
Answered by
6
Lets analyze the equations :
1) x(y - 5) = 2
Opening the brackets.
xy - 5x = 2
Given we have xy the equation is not linear.
2) y - 2(x + 9) = 0
y - 2x - 18 = 0
Y = 2x + 18
This is linear
3) 3y + 6(2 - x) = 5
3y + 12 - 6x = 5
3y = 5 - 12 + 6x
3y = 6x - 7
Y = 2x - 7/3
This is linear
4) 2(y + x) = 0
2y + 2x = 0
2y = - 2x
y = - x
This is linear.
Answered by
1
Thank you for asking this question:
1) x(y - 5) = 2
Opening the brackets.
xy - 5x = 2
Given we have xy the equation is not linear.
2) y - 2(x + 9) = 0
y - 2x - 18 = 0
y = 2x + 18
This is linear
3) 3y + 6(2 - x) = 5
3y + 12 - 6x = 5
3y = 5 - 12 + 6x
3y = 6x - 7
y = 2x - 7/3
This is linear
4) 2(y + x) = 0
2y + 2x = 0
2y = - 2x
y = - x
So this means that this is linear.
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