Question

A particle has an initial velocity of 9 m/s due east
and a constant acceleration of 2m/s2 due west. The
distance covered by the particle in the fifth second
of its motion is:​

Answer 1

Answer:

A=0

Explanation:

initial velocity u=9 due east

acceleration a=-2 m/S2( minus because acceleration is due west )

so distance covered in 5 seconds =9×5-0.5×2×5×5

distance covered in 4 seconds =9×4-0.5×2 ×4×4×=20 meters

hence there is no movement in the 5th second

correct answer is A=0