Question

A particle has initial velocity (2î +3j) and
acceleration (0.3î +0.2j). The magnitude of
velocity after 10 seconds will be
​

Answer 1

intial velocity of the particle (u) =2i+3j

it's magnitude =square root of (2²+3²)

=square root of 13

magnitude of acceleration =square root of (.13)

time =10sec

by, v=u+at

v=root of 13 + root of(.13)*10

v=2*root(13) meter /sec