Question

A particle has initial velocity ,v= 9i_6j m/s and a constant f= 2i+ 3j n acts on the particle . The path of particle will be

Answer 1

Answer:circular path

Explanation:

You can check vector are perpendicular to each other

I.e dot product of vectors should be equal to zero

V. f= 0

9*2-6*3

=0

So force and velocity are 90 to each other they go in circular motion

Learnt in uniform circular motion NCERT 11TH