Physics, asked by twinklegupta436, 1 year ago

A particle having charge q is fixed at a point o and a second particle of mass m amd having charge (-q) moves with constant speed in a circle of radius r about the charge q the energy required to be supplied to the moving charge to increase the radius of the path to 2r is

Answers

Answered by Robin0071
4
Solution:-

given by:-

W=Change in ( OE)

=(1/4πε0)×(q1q2/r1−q1q2/r2)

=1/4πε0(qQ/r1−qQ/r2)

=(qQ/4πε0(1/r1−1/r2))ans

☆i hope its help☆





Answered by MrShivam11
1

Answer:

Explanation:

Solution:-

given by:-

W=Change in ( OE)

=(1/4πε0)×(q1q2/r1−q1q2/r2)

=1/4πε0(qQ/r1−qQ/r2)

=(qQ/4πε0(1/r1−1/r2))ans

☆i hope its help☆

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