A particle having charge q is fixed at a point o and a second particle of mass m amd having charge (-q) moves with constant speed in a circle of radius r about the charge q the energy required to be supplied to the moving charge to increase the radius of the path to 2r is
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Answered by
4
Solution:-
given by:-
W=Change in ( OE)
=(1/4πε0)×(q1q2/r1−q1q2/r2)
=1/4πε0(qQ/r1−qQ/r2)
=(qQ/4πε0(1/r1−1/r2))ans
☆i hope its help☆
given by:-
W=Change in ( OE)
=(1/4πε0)×(q1q2/r1−q1q2/r2)
=1/4πε0(qQ/r1−qQ/r2)
=(qQ/4πε0(1/r1−1/r2))ans
☆i hope its help☆
Answered by
1
Answer:
Explanation:
Solution:-
given by:-
W=Change in ( OE)
=(1/4πε0)×(q1q2/r1−q1q2/r2)
=1/4πε0(qQ/r1−qQ/r2)
=(qQ/4πε0(1/r1−1/r2))ans
☆i hope its help☆
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