Question

find the altitude of a Trapezium, the sum of the lengths of whose base is 6.5 cm and whose area is 26 CM square

Answer 1

I have not got the correct answer please give me the correct answer please . it is not matching with my book and it is not 26 the area is 65

Answer 2

Answer:

$Altitude \: of \: the \\ trapezium (h) = 8 \:cm$

Step-by-step explanation:

Let a and b are two parallel sides of a trapezium .

Given ,

a+b = 6.5 cm ,

Let altitude = h cm

Area of the trapezium (A)=26 cm²

$\frac{1}{2}\times (a+b)h=26$

$\implies \frac{1}{2}\times 6.5 \times h = 26$

$\implies h = \frac{26\times 2}{6.5}\\=4 \times 2 \\=8\:cm$

Therefore,

$Altitude \: of \: the \\ trapezium (h) = 8 \:cm$

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