Physics, asked by saritaniraj1818, 1 year ago

A particle having constant velocity u is moving with acceleration a in time t find (a) displacement of particle in last one second (b) evaluate displacement for u =2m/s, a=1m/s^2 ,t=5 seconds

Answers

Answered by saeshwaran2099pdpr5g
0
s= ut + at^2/2
by substituting we get s= 2*5+1*5*5
s= 10+25
= 35
displacement in nth second = a/2(2n-1)
by substituting we get s(n) = 1/2(10-1)
= 9/2 = 4.5

saeshwaran2099pdpr5g: please correct me if i am wrong
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