Question

A particle having initial velocity 10 m/s

moves with a constant acceleration 5 ms–2

,

for a time 15 second along a straight line,

what is the displacement of the particle in

the last 2 second​

Answer 1

Answer:

Displacement in last 2 secs = 160 m

Explanation:

Given , Initial velocity = 10m/s

Acceleration = 5m/s²

time = 15 sec

We know , s = ut + 1/2× at²

s = 10× 15 + 1/2 × 5×15×15

s = 150+1125/2

s = 712.5 m

Therefore , s in last 2 sec = displacement in 15 secs - displacement in first 13 secs = 712.5 - 10×13 - 1/2 × 5 × 13² = 712.5 - 130 - 422.5 = 160 m