A particle having initial velocity u moving with a constant acceleration for time T find displacement of particle in last evaluate for u =2m/sce, a =1m/sce and t =5sce
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Hola........
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QUESTION:- A particle having initial velocity u moving with a constant acceleration for time T find displacement of particle in last evaluate for u =2m/sce, a =1m/sce and t =5sce
ANSWER:- given
S=ut+1/2(at)^2
2x5+12.5
S=22.5
T=5sec
S=10+0.5
=10.5
_____________________________________________________________
Hope it helps
_____________________________________________________________
QUESTION:- A particle having initial velocity u moving with a constant acceleration for time T find displacement of particle in last evaluate for u =2m/sce, a =1m/sce and t =5sce
ANSWER:- given
S=ut+1/2(at)^2
2x5+12.5
S=22.5
T=5sec
S=10+0.5
=10.5
_____________________________________________________________
Hope it helps
Answered by
2
Hey! ! !
Solution :-
☆ Total distance=s =ut+1/2at^2
● where u=5m/s a=2m/s^2 & t=10s S10th=u+a/2(2*n -1)
● where a=2 m/s^2 n=10s (1) V at 9th sec. =u at 10th sec. v= u + at
●where u=5 a=2 &t=9
● This v is initial velocity of 10th sec. and can be put into (1) eq. Hence ,Snth can be calculated.
☆ ☆ ☆ Hop its helpful to you ☆ ☆ ☆
☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
Solution :-
☆ Total distance=s =ut+1/2at^2
● where u=5m/s a=2m/s^2 & t=10s S10th=u+a/2(2*n -1)
● where a=2 m/s^2 n=10s (1) V at 9th sec. =u at 10th sec. v= u + at
●where u=5 a=2 &t=9
● This v is initial velocity of 10th sec. and can be put into (1) eq. Hence ,Snth can be calculated.
☆ ☆ ☆ Hop its helpful to you ☆ ☆ ☆
☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
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