Question

A particle in the x-y plane is located at a distance 5 m from the origin at an angle of 37owith x-axis. The position vector is​

Answer 1

Answer:

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Answer 2

Given :

Distance = 5m

angle with x axis =$37$

to find :

the positional vector

solution :

we know that ,

$cos 37 =\frac{4}{5} \\sin 37 =\frac{3}{5}$

positional vector = r(cosx i + sin x j)

positional vector = $5(cos37 i +sin37j )=5(\frac{4}{5} i+\frac{3}{5}j)=4i+3j$

Hence positional vector is 4i+3j

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