Question

A particle initially at rest starts moving with a uniform acceleration a . The ratio of the distances covered by it in first second and the first 4 seconds will be

Answer 1

Answer:

1 : 16

Explanation:

Using equations of motion,

Distance travelled in nth second (Sn)

= initial velocity + acceleration(n - 1/2)

Therefore

S1 = 0 + a(1 - 1/2)

S1= a/2

Distance travelled in n seconds = initial velocity * time + 1/2 * a * time²

Therefore

S = 0 + 1/2 * a * 4²

S = 8a

Therefore,

S1 : S = a/2 : 8a

= 1 : 16

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