Question

A particle is acted upon by constant magnitude force perpendicular to it which is always perpendicular to velocity of particle. The
motion is taking place in a plane it follows that
(A) velocity is constant
(B) acceleration is constant
(C) kinetic energy is constant
(D) it moves in circular path

Answer 1

Answer:

(C) kinetic energy is constant

Explanation:

Since the particle is acted upon by a force of constant magnitude which is always perpendicular to the velocity of the particle, so work done by the force in the direction of the velocity is zero. So the magnitude of velocity will not change due to the force.

Kinetic energy is KE= 1/2 $(mv)^{2}$ =constant.

Now mass and magnitude of velocity will always be constant in this given situation so the kinetic energy will also be constant.

Hence, the correct option is (C)

Hope I helped!

Answer 2

HELLO MATE!!! Here is your answer....

It will not change the magnitude of velocity

It only change the direction of the velocity.

Thus the particle is in a uniform motion....

PLS MARK IT AS BRANLIEST...