A particle is at origin initially and moves along x axis it's velocity v as time t is given by v=10-2t the distance travelled by its in first 8s is
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Answer:
a= 2t^5
dv/=2t^5dt
Integrating
v=2t^6/6 + const.
When t= 0
v=0 so const = 0
v=t^6/3
When t= 2sec.
v=64//3 m/sec.
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Explanation:
Answered by
2
Answer:
a= 2t^5
dv/=2t^5dt
Integrating
v=2t^6/6 + const.
When t= 0
v=0 so const = 0
v=t^6/3
When t= 2sec.
v=64//3 m/sec.
PLZ FOLLOW ME
Explanation:
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