Math, asked by bichananda123, 4 months ago

integration sin²x cos³x dx

Answers

Answered by luckyprathluckyprath

3

ʃ sin²x cos²x cosx dx

ʃ sin²x (1-sin²x) cosx dx

Let u=sinx

du = cosxdx

ʃu²(1-u²)du

ʃ(u²-u⁴)du

ʃ(u²-u⁴)du

⅓ u³ - ⅕u⁵ + C

⅓ sin³x - ⅕sin⁵x + C

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