A particle is at x = +5 m at t = 0, x = -7m at t = 6s and x = +2m at t = 10s. Find the average velocity of the particle during the interval (a) t = 0 to t = 6s; (b) t = 6s to t = 10s, (c) t = 0 to t = 10s.
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Explanation:
since avevelocityrage
=( final position-initial position ) / interval of time
(a) = { -7- 5} / (6-0)
= -12 / 6
= - 2 m/s
(b) = {+2-(-7)} / ( 10-6)
= 9/4
= 4.5 m/s
(c) = (2-5) / (10-0)
= -3/10
= - 0.33m/s
negative value of velocity shows the direction
of velocity towards left to the real line.
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