Physics, asked by kashyapnaveen6164, 7 months ago

A particle is at x = +5 m at t = 0, x = -7m at t = 6s and x = +2m at t = 10s. Find the average velocity of the particle during the interval (a) t = 0 to t = 6s; (b) t = 6s to t = 10s, (c) t = 0 to t = 10s.

Answers

Answered by rajivrtp
3

Explanation:

since avevelocityrage

=( final position-initial position ) / interval of time

(a) = { -7- 5} / (6-0)

= -12 / 6

= - 2 m/s

(b) = {+2-(-7)} / ( 10-6)

= 9/4

= 4.5 m/s

(c) = (2-5) / (10-0)

= -3/10

= - 0.33m/s

negative value of velocity shows the direction

of velocity towards left to the real line.

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