A particle is displaced by 8m east and then it is displaced by 6m north. What is the resultant displacement of the particle?
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Explanation:
Consider, east direction to be x-direction, north direction to be y-direction and vertically upward direction to be z-direction.
Displacement of the particle is given by
S
=8
i
^
+6
j
^
+10
k
^
Magnitude of displacement ∣
S
∣=
6
+8
2 +10 2
=10 2 m
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