Question

A particle is dropped from a height 20 m apart from gravity the particle attains an additional constant horizontal acceleration of 10 metre per second square due to wind the displacement of the particle when it reaches the ground will be ​

Answer 1

Answer:

Its displacement will be 20 m only because displacement is the shortest distance the body could have travelled, as it is placed at a height of 20m, its shortest distance will be 20m. After deflection of wind, the length that it will cover to reach the ground will be distance. So DISPLACEMENT IS 20M.

Brainliest? Do mark.

Answer 2

Answer:

vertical displacement is 20 m

horizontal displacement=20√2 m

Explanation:

using

s =ut +1/2 at^2

u will be 0 since it is dropped

in y axis

20= 1/2×-10 t^2

20=-5t^2

t= 2 s

in x axis

horizontal acceleration and vertical acceleration is 10 m/s^2 using vectors the net acceleration is 10√2 in

s=ut+1/2at^2

s=1/2×10√2×2^2

s=20√2=horizontal displacement