Question

A particle is dropped from a tower 180 metre high . how long does it take to reach the ground what is its velocity when it touches the ground .
please give answer to get brainlist

Answer 1

here , 

h = 180 m 

u = 0 m/s 

a = g = 9.8 m/s

v = u + at 

v = gt 

t = v/9.8 

and , 

s = ut + 1/2 at²

180 = 1/2 gt²

180 = v²/9.8

180 x 9.8 = v²

v = 42 m/s 

t = 42/9.8 

t = 4.28 seconds 

Answer 2

Answer:

H=180m

g=10m/s^2

u=0m/s

Formula:

H=ut+1/2gt^2

180=0×t+1/2(-10)t^2

180=5t^2

t=5/180

t=36

time taken for coming down is 36m/s