Question

A particle is dropped from a tower. It takes 2.4 secs to reach the ground. What is the final lvelocity of the particle.

Give me correct answer please​

Answer 1

Answer:

the final velocity of particle will be hight × time

displacement over time

Answer 2

Answer:

125m

Explanation:

The distance covered in first 3 second

s=

2

1

gt

2

=12×10×3

2

=45

If the ball takes 'n' second to fall to the ground. The distance covered in n

th

second

s

n

=u+

2

g

(2n−1)

=0+

2

10

(2n−1)

=10n−5

Therefore,

45=10n−5

n=5

Therefore,

h=

2

1

gt

2

=

2

1

×10×25

=125m

Thus the height of the tower is 125m