Physics, asked by Tosifansari7363N, 1 year ago

A particle is dropped from a tower.it takes 2.4s to reach the ground.What is the final velocity of the particle?

Answers

Answered by abhinav27122001
11

Here's your answer mate..

Good luck ✌️

Attachments:

Tosifansari7363N: Yours answer is wrong
Tosifansari7363N: Answer is 23.5m/s
abhinav27122001: It is 23.5 if u take the value of acceleration due to gravity 'g' as 9.8
Answered by rinayjainsl
1

Answer:

The final velocity of particle is -23.54m/s

Explanation:

Given that,

A particle is dropped from tower.Therefore its initial velocity is zero.

 =  > u = 0

Also given,it takes 2.4sec for the particle to reach ground.

To find final velocity of particle,we use the kinematic equation of motion for a freely falling body

v = u  + at

We know that u=0 and a=-g

 =  > v = 0 + ( - g)(t) \\  =  > v =  - 9.81 \times 2.4  \\ =  - 23.54ms {}^{ - 1}

Negative sign indicates that the velocity is in vertically downward direction

#SPJ3

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