Question

A particle is dropped from the top of a tower .It covers 9/25 part of height of tpwer in the last second then find the height of tower

Answer 1

Hi there,

Let,
Height of tower = H

Total time taken to reach the ground = T

16H/25 = 0.5gT^2 ——-(1)
9H/25

= 0.5g (T - 1)^2

Divide above two equations

16 / 9 = (T / (T -1))^24 / 3

= T / (T - 1)
3T = 4T - 4

T = 4 s

Substitute T = 4s in equation (1)
16H / 25 = 0.5g * 4^2
H = (25/16) * 0.5 * 9.8 * 16
H = 122.5 m

hence,Height of the tower is 122.5 m