A particle is dropped from the top of the tower of height 20 m.Find (a)time taken to reach the ground(b)velocity with which it hits the ground (c)height fallen in the last sec of its fall.
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h=ut+1/2at^2
here, u=0 a=g
h=1/2 gt^2
(a)
20=1/2×10t^2
t^2=4
t=2sec
(b)
v=u+at
u=0 a=g
v= 10×2
=20m/sec
(c)
height in 1st sec, h1= 1/2gt^2
h1=1/2×10×1^2
h1= 5
height fallen in last sec = total height - h1
=20 - 5
=15m
here, u=0 a=g
h=1/2 gt^2
(a)
20=1/2×10t^2
t^2=4
t=2sec
(b)
v=u+at
u=0 a=g
v= 10×2
=20m/sec
(c)
height in 1st sec, h1= 1/2gt^2
h1=1/2×10×1^2
h1= 5
height fallen in last sec = total height - h1
=20 - 5
=15m
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