a particle is dropped from top of a tower .it covers 40 m in last 2 second.find height of tower
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Answer:
80 m
Explanation:
in 1sec traveling 20m
v^2-u^2=1/2as
v=20m/s, u = 0m/s and a= 10m/s^2
(20m/s)^2-0= 1/2 * 10m/s^2* s
s=80m
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