Physics, asked by kabhishekh511, 11 months ago

A particle is executing s.H.M its total energy is

e.Calculate its potential energy and kinetic enargy when the displacement is half of the omplitude

mariatahir06: According to the given condition
x=xo/2
K.E =1/2k (xo2-x2)
Put x=xo/2 here
So by solving we get
K.E =3/4 of the total energy which is 0.75 of total energy that is 75%

For P.E
P.E =1/2kx2
Now here put x=xo/2
So p.e becomes 1/4 of the total energy that is 0.25 of total energy or 25%

Hope it helps

Answers

Answered by Sonalibendre

0

what is ur question

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