Question

A particle is executing S.H.M. of amplitude 5cm and period of 2s. Find the speed of the particle at a point where its acceleration is half of its maximum value.
(Ans: 13.6 cm/s)

Answer 1

Answer:

13.6 cm/s

Explanation:

Given A particle is executing S.H.M. of amplitude 5cm and period of 2s. Find the speed of the particle at a point where its acceleration is half of its maximum value.  

 Now given A = 5 cm , T = 2 secs

We know that a = Aω^2 / 2, to find v

        Because a = a max / 2

 So ω^2 x = Aω^2 / 2

  W e get x = A / 2

We know that v = ω √A^2 – x^2, also ω = 2π/T

So v = 2π/T √A^2 – A^2 / 4

    V = 2π/T √3 A/2

   V = 3.14 x √3 x 5 / 2 (A = 5 cm)

 V = 13.6 cm