Question

A particle is executing shm about along y axis such that its velocity are v1 and v2 at distance y1 and y2 from the mean position . Calculate time period of motion

Answer 1

Hope this helps you !!!

Answer 2

Answer:

Easy

Explanation:

Using the expressions for velocity for SHM,

v

1

=ω

A

2

−x

1

2

v

2

=ω

A

2

−x

2

2

Squaring both,

v

1

2

=ω

2

(A

2

−x

1

2

) ....(3)

v

2

2

=ω

2

(A

2

−x

2

2

) ....(4)

Subtracting (4) from (3), v

1

2

−v

2

2

=ω

2

(x

2

2

−x

1

2

)

⇒4π

2

(x

2

2

−x

1

2

)=T

2

(v

1

2

−v

2

2

)

⇒T=2π

v

1

2

−v

2

2

x

2

2

−x

1

2

where we have used ω=

T

2π