Question

A triangular loop of side l carries a current i. It is placed in a magnetic field b such that the plane of the loop is in the direction of b. The torque on the loop is

Answer 1

Explanation:

Triangular loop of side having length=L and magnetic field=B

When current(i) is passed through the loop having area (A), then the magnetic dipole moment is given by,

M=iA where, A is the area of the coil

A=

2

1

×base×height=

2

1

×l×lsin60=

4

3

l

2

Therefore magnetic dipole moment is,

M=iA=

4

3

il

2

The angle between the normal of the plane and the applied magnetic field is 90 degree

Now the torque acting on the loop is,

τ=MBsinθ=

4

3

il

2

Bsin90=

4

3

iBl

2

Answer 2

Answer:

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