Physics, asked by amansood7897, 1 year ago

A particle is executing simple harmonic motion (shm) of amplitude a, along the x-axis, about when its potential energy (pe) equals kinetic energy (ke), the position of the particle will be:

Answers

Answered by titan0
1

kinetic energy in shm

= 1/2 kx^2

potential energy in shm

= 1/2 k (a^2-x^2)

equalise them

you will get

x^2 = a^2-x^2

x^2 = a^2/2

x = a/root2

HOPE IT WILL HELP YOU

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