A particle is moving on straight path. If initial velocity is 8 ms18 ms1 and acceleration is 2 ms22 ms2 then distance travelled by the particle in initial 5 second will be :
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Explanation:by using the laws of motion
S= (ut) + 0.5 at^2 we get
S = 8x5 + 0.5 x 2 x (5) ^2
S = 40 + 25
S = 65m.
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