Question

A particle is fired from ground with speed u making an angle theta with the horizontal. The speed of the particle just before hitting the ground will be

$please \\ answer \: it \: fast$
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Answer 1

Answer:

let,

velocity=v

Time taken by projectile=t

initial velocity =u

Angle =theta

we know ,

1. when time flight is given,

• u= tg/2sin(theta)

1. when Horizental range is given,

• u=Rg/sin(2theta)