A particle is in a unidirectional potential field where the potential energy ( U ) of a particle depends on the x coordinate given by Ux = K (1-cos ax) and K and a are constants. Find the physical dimension of a and K.
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We know that U represents Potential Energy and its Dimension are [ ML²T⁻² ]
Now,
The Argument of Cosine Function is always a number, so ax is a number
Thus, [a]= [x]⁻¹
also x is the coordinates, so it represents length
so Dimension of a , [a]=[M⁰L⁻¹T⁰]
Now, (1-cos ax) is dimensionless, so the Dimensions of K , [K]=[U]
[K]= [ ML²T⁻²]
Solved
Now,
The Argument of Cosine Function is always a number, so ax is a number
Thus, [a]= [x]⁻¹
also x is the coordinates, so it represents length
so Dimension of a , [a]=[M⁰L⁻¹T⁰]
Now, (1-cos ax) is dimensionless, so the Dimensions of K , [K]=[U]
[K]= [ ML²T⁻²]
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