sin2A=2sinA. it is true ,what is the value of A
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when A=0 then it is correct
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sin2A=2sin
or sin2A−2sinA=0
sinA(sinA−2)=0
but sinA≠2 because sinA lies between −1 to 1 so, sinA=0or A=0
or sin2A−2sinA=0
sinA(sinA−2)=0
but sinA≠2 because sinA lies between −1 to 1 so, sinA=0or A=0
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