A particle is initially at rest and starts with an acceleration of 2 metre per second square then find the velocity of the particle at t is equals to 2 second
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u = 0m/s
a = 2m/s^2
t= 2 sec
v = u + at
= 0 + 2*2
= 4m/s
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Answered by
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Answer:
Explanation:
as particle is initially at rest
so,
u=0 m/s
given, a=2m/s² and t=2 sec
using first eq of motion,
v=u+at
v=0+2×2
v=4m/s
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