A particle is initially at rest. It starts moving with a constant acceleration,
The speed of the particle in t seconds is 50 m/s and after one second the
speed becomes 75 m/s. Calculate the acceleration of the particle and distance
covered in (t + 1)th second of its motion.
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Answer:
mafk as brainilist
Explanation:
u=0,v=18 km/hr=5 m/s,t=5 sec
a=
t
v−u
=
5
5−0
=1 m/s
2
s=ut+
2
1
at
2
=12.5 m/s
2
(a) Average velocity V
ave
=(12.5)/5=2.5 m/s
(b) Distance travelled is 12.5 m.
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