Physics, asked by remruati281994, 6 months ago

A particle is initially at rest. It starts moving with a constant acceleration,
The speed of the particle in t seconds is 50 m/s and after one second the
speed becomes 75 m/s. Calculate the acceleration of the particle and distance
covered in (t + 1)th second of its motion.​

Answers

Answered by krishnadeepaunni
0

Answer:

mafk as brainilist

Explanation:

u=0,v=18 km/hr=5 m/s,t=5 sec

a=

t

v−u

=

5

5−0

=1 m/s

2

s=ut+

2

1

at

2

=12.5 m/s

2

(a) Average velocity V

ave

=(12.5)/5=2.5 m/s

(b) Distance travelled is 12.5 m.

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