A particle is kept at rest at a distance R (earth's radius) above the earth's surface. The minimum speed with which it should be projected so that it does not return is
(a) √GM4R
(b) √GM2R
(c) √GMR
(d) √2GMR
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The answer is option (c).
Explanation:
At a distance R from the earth’s surface, the particle has the potential energy is
P.E.i = 12GMmR = GMm (R+R),
where M = mass of the earth;
R = radius of the earth
m = body mass
Let the projection of the particle be with the speed v. It just escapes the earth’s gravitational pull.
So, the body’s kinetic energy = -[change in the body’s potential energy]
Now, the body’s kinetic energy = -[- initial potential energy + final potential energy]
⇒12mv2 = -GMm∞ - GMm2R
⇒v = GMmR
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