Question

A particle is motion and is accelerating functional form of velocity is V (t) = 20t- 5t^2 metre per second. Find instantaveous velocity at t=1,2,3and 5

Answer 1

Answer:

Explanation: The instantaneous velocity is given by dsdt . Since s(t)=t3+8t2−t , dsdt=3t2+16t−1 . At t=2 , [dsdt]t=2=3⋅22+16⋅2−1=43 .

Explanation:

Answer 2

V(t)= 20t-5t^2

At t=1s

V(1) = 20-5= 15m/s

At t=2s

V(2) = 20(2) - 5(4) = 20m/s

At t=3s

V(3) = 20(3) - 5(9) = 15 m/s

At t=5s

V(5) = 20(5) - 5(25) = -25m/s

No integration or differentiation required we just only have to put the values.

Hope it helps!